2(x-1)^2-1=3(2x+1)+1

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Solution for 2(x-1)^2-1=3(2x+1)+1 equation: 



2(x-1)^2-1=3(2x+1)+1

We move all terms to the left:

2(x-1)^2-1-(3(2x+1)+1)=0



We calculate terms in parentheses: -(3(2x+1)+1), so:

3(2x+1)+1

We multiply parentheses

6x+3+1

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

2(x-1)^2-6x-4-1=0

We add all the numbers together, and all the variables

-6x+2(x-1)^2-5=0

We move all terms containing x to the left, all other terms to the right

-6x+2(x-1)^2=5

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